Commutative diagrams side by side have different sizes
Within the statement of a theorem, I have two commutative diagrams. I am trying to use pb-diagram to create them, and I would like them to be side by side. Unfortunately the size of the commutative diagrams seem to depend on the size of the symbols at the nodes, and the two commutative diagrams come out to be different sizes. Is there any way to fix this?
Here is the code I have right now:
\begin{equation}
\begin{diagram}
\node{\C_R}\arrow{e,t}{P}\arrow{s,l,J}{\Psi}\node {\C_R}\arrow{s,l,J}{\Psi}\\
\node{\Chat_R}\arrow{e,t}{E(P)}\node{\Chat_R}
\end{diagram}\hspace{40pt}
\begin{diagram}
\node{\C_{R,\,\top}}\arrow{e,t}{P}\arrow{s,l,J}{\Psi}\node {\C_{R,\,\top}}\arrow{s,l,J}{\Psi}\\
\node{\Chat_{R,\,\top}}\arrow{e,t}{E(P)}\node{\Chat_{R,\,\top}}
\end{diagram}
\end{equation}
and here is the result of compiling:
Within the statement of a theorem, I have two commutative diagrams. I am trying to use pb-diagram to create them, and I would like them to be side by side. Unfortunately the size of the commutative diagrams seem to depend on the size of the symbols at the nodes, and the two commutative diagrams come out to be different sizes. Is there any way to fix this?
Here is the code I have right now:
\begin{equation}
\begin{diagram}
\node{\C_R}\arrow{e,t}{P}\arrow{s,l,J}{\Psi}\node {\C_R}\arrow{s,l,J}{\Psi}\\
\node{\Chat_R}\arrow{e,t}{E(P)}\node{\Chat_R}
\end{diagram}\hspace{40pt}
\begin{diagram}
\node{\C_{R,\,\top}}\arrow{e,t}{P}\arrow{s,l,J}{\Psi}\node {\C_{R,\,\top}}\arrow{s,l,J}{\Psi}\\
\node{\Chat_{R,\,\top}}\arrow{e,t}{E(P)}\node{\Chat_{R,\,\top}}
\end{diagram}
\end{equation}
and here is the result of compiling:
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